The angles x – 10° and 190° – x are (iii) uncommon arms are always opposite rays. Can two acute angles form a pair of supplementary angles? (a) Since, POR is a line. We know that, sum of two complementary angles is 90°. (i) each pair of vertically opposite angles, and Class 7 Maths Lines and Angles . A linear pair may have two acute angles. Then, ∴ EF and GH are not parallel lines. Question 27: Now, SP || RQ and PR is a transversal. So, the sum of two right angles = 90° + 90° = 180°. False Mathematics NCERT Grade 7, Chapter 5: Lines and Angles is all about different lines, line segments, and angles. Solution: ∴ ∠2 + 75° = 180° [Co-interior angles] (c) vertically opposite                                 (d) making a linear pair Solution : Here we have provided NCERT Exemplar Problems Solutions along with NCERT Exemplar Problems Class 7.. NCERT Exemplar Class 7 Maths Unit 5 Lines and Angles. (iv) c and f (c) 36° (d) 120° If a transversal intersects two parallel lines and the difference of two interior angles on the same side of a transversal is 20°, find the angles. p: a and bare forming a linear pair. This chapter throws light on topics such as related angles, pair of lines. (b) one of its angles is obtuse? ∴These angles are supplementary. (b) one of its angles is obtuse? (b) 4 types of angles are formed i.e., vertically opposite angles, adjacent angles, supplementary angles and linear pairs. Give reason. According to question, ∴ A and bare alternate interior angles. An angle is 45°. As two acute angles can make a pair of complementary angles. Solution : Question 67. Solution : ∴ ∠4 = 75° [Alternate interior angles], Question 91. 5. Solution : (i) Since, PQ || UT and PT is transversal. Let one angle be x. ∠POR + 5 ∠POR = 90° ⇒ 50° + ∠QPR – 130° (d) supplementary angles ⇒ 3a – b + 2a + b = 180 ⇒ 5a = 180 Solution: Complementary ⇒ 4x = 180° Question 53: Solution: 45° It is given that x° makes a linear pair with 61°. (a) From the given figure it is clear that. (d) 150° Solution : Q11 exercise-5-1 Lines and Angles NCERT Solutions. NCERT Solutions for Class 7 Mathematics CBSE, 5 Lines And Angles. Solution: (ii) Name all the pairs of complementary angles. ∴ ∠SPQ = ∠PQU [Alternate interior angles] Solution : (e) Since, POQ is a straight line. Putting value of x in (i), we get (ii) No, a and b are not adjacent angles as they don’t have common arm. Solution : Iron rods a, b, c, d, e and f are making a design in a bridge as shown in the given figure, in which a|| b, c || d and e|| f. Find the marked angles between Now, ∠PQR = ∠PQU + ∠UQR (a) how many angles are formed? (c) (i) is false but (ii) and (iii) are true e.g. (a) 120°                     (b) 60°                      (c) 30°                        (d) 20° ∠1 and ∠8; ∠2 and ∠7; ∠3 and ∠4; ∠4 and ∠5; ∠5 and ∠6; ∠3 and ∠6 are six pairs of supplementary angles. Solution: (b) 46° Solution: In the given figure, PA || BC|| DT and AB || DC. Solution : Question 112: Two supplementary angles always form a linear pair. Since, two angles form a linear pair. Two angles are making a linear pair. NCERT Solutions for Class 7 Maths Chapter 5 Lines and Angles Exercise 5.1 and Exercise 5.2 in English Medium and Prashnavali 5.1 and Prashnavali 5.2 in Prashnavali to study online or download in PDF file for offline free to use. Then, ∠QOS measures (c) 70°, 110° (c) 90° In the given figure, l, m and n are parallel lines, and the lines p and q are also parallel. Angles which are both supplementary and vertically opposite are ⇒                                    x = 180° – 61°= 119°. (iv) No, a and b are not adjacent angles as the arms which are not common are on the same side of common arm. In the given figure, POQ is a line. Thus, one angle is 100° and other is 80°. (b) 50°, 20° ⇒ ∠x = 180° – 120° = 60° Adjacent angles: ∠x, ∠y; ∠x + ∠y, ∠z; ∠y, ∠z; ∠x, ∠y + ∠z. (b) Since ∠POR and ∠QOS are in the ratio 1 : 5 Let angles will be x and 5x, respectively. Solution : Maths Class 5 Lines and Angles Exercise 5.2 NCERT Solutions are extremely helpful while doing your homework or while preparing for the exam. ∴ ∠AOE + ∠EOD + ∠DOB = 180° Therefore, B will be less than 45°. We have provided Lines and Angles Class 7 Maths MCQs Questions with Answers to help students understand the concept very well. Solution: ∴ a + b = c [Alternate interior angles] Now, l is a straight line. (i) ∠AOD and ∠DOB; ∠DOB and ∠BOC, ∠BOC and ∠AOC; ∠AOC and ∠AOD are four pairs of supplementary angles. 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